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18b^2-90b+70-2=0
We add all the numbers together, and all the variables
18b^2-90b+68=0
a = 18; b = -90; c = +68;
Δ = b2-4ac
Δ = -902-4·18·68
Δ = 3204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3204}=\sqrt{36*89}=\sqrt{36}*\sqrt{89}=6\sqrt{89}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-6\sqrt{89}}{2*18}=\frac{90-6\sqrt{89}}{36} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+6\sqrt{89}}{2*18}=\frac{90+6\sqrt{89}}{36} $
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